21=45.3/m^2

Solution for 21=45.3/m^2 equation:

21=45.3/m^2

We move all terms to the left:

21-(45.3/m^2)=0


Domain of the equation: m^2)!=0

m!=0/1

m!=0

m∈R


We get rid of parentheses

-45.3/m^2+21=0

We multiply all the terms by the denominator


21*m^2-45.3=0

We add all the numbers together, and all the variables

21m^2-45.3=0

a = 21; b = 0; c = -45.3;
Δ = b2-4ac
Δ = 02-4·21·(-45.3)
Δ = 3805.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{3805.2}}{2*21}=\frac{0-\sqrt{3805.2}}{42}
=-\frac{\sqrt{}}{42}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{3805.2}}{2*21}=\frac{0+\sqrt{3805.2}}{42}
=\frac{\sqrt{}}{42}
$